Factor the trinomial completely.
-$5 x ^ { 4 } + 13 x ^ { 2 } - 6$
A) $\left( 5 x ^ { 2 } + 3 \right) \left( x ^ { 2 } - 2 \right)$
B) $\left( 5 x ^ { 2 } - 2 \right) \left( x ^ { 2 } + 3 \right)$
C) $\left( 5 x ^ { 2 } + 2 \right) \left( x ^ { 2 } - 3 \right)$
D)prime

Question

Quizplus · Accepted Answer

To factor the trinomial $5x^4 + 13x^2 - 6$, we look for two binomials $(ax^2 + b)(cx^2 + d)$ such that $ac = 5$, $bd = -6$, and $ad + bc = 13$. The correct combination is found in option B, where $5x^2 - 2$ and $x^2 + 3$ multiply to give the original trinomial.

Factor the Trinomial Completely 5x4+13x2−65 x ^ { 4 } + 13 x ^ { 2 } - 65x4+13x2−6

Factor the Trinomial Completely $5 x ^ { 4 } + 13 x ^ { 2 } - 6$