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Find the Derivative at Each Critical Point and Determine the Local

Question 42

Multiple Choice

Find the derivative at each critical point and determine the local extreme values.
- y={62x,x1x+3,x>1y = \left\{ \begin{array} { l } 6 - 2 x , x \leq 1 \\x + 3 , x > 1\end{array} \right.


A)
 Critical Pt.  derivative  Extremum  Value x=1 undefined  minimum 4\begin{array}{l|l|l|l}\text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\\hline x=1 & \text { undefined } & \text { minimum } & 4\end{array}

B)
 Critical Pt.  derivative  Extremum  Value x=2 undefined  minimum 5\begin{array}{l|l|l|l}\text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\\hline x=2 & \text { undefined } & \text { minimum } & 5\end{array}

C)
 Critical Pt.  derivative  Extremum  Value x=10 minimum 4\begin{array}{l|l|l|l}\text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\\hline x=1 & 0 & \text { minimum } & 4\end{array}

D)
 Critical Pt.  derivative  Extremum  Value x=00 minimum 5\begin{array}{l|l|l|l}\text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\\hline x=0 & 0 & \text { minimum } & 5\end{array}

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