Find the extreme values of the function and where they occur.
-$$y = \frac { 7 } { \sqrt { 1 - 9 x ^ { 2 } } }$$
A) The maximum is 7 at x = 2.
B) The minimum is 7 at x = 0.
C) The minimum is 0 at x = 1.
D) The maximum is 7 at x = -2.

Question

Quizplus · Accepted Answer

The function $\frac{7}{\sqrt{1-9x^2}}$ has a minimum value when the denominator is at its maximum, which occurs when $x = 0$, making the function value $y = \frac{7}{\sqrt{1-9(0)^2}} = 7$. There are no maximum values since the function approaches infinity as $x$ approaches $\pm\frac{1}{3}$.

Find the Extreme Values of the Function and Where They y=71−9x2y = \frac { 7 } { \sqrt { 1 - 9 x ^ { 2 } } }y=1−9x2​7​

Find the Extreme Values of the Function and Where They $y = \frac { 7 } { \sqrt { 1 - 9 x ^ { 2 } } }$