Eliminate the parameter.
-$$x = t - 3 , y = t ^ { 2 } + 5$$
A) $y = x ^ { 2 } - 14$
B) $y = x ^ { 2 } + 14$
C) $y = x ^ { 2 } - 6 x - 14$
D) $y = x ^ { 2 } + 6 x + 14$

Question

Quizplus · Accepted Answer

To eliminate the parameter, solve for $t$ in terms of $x$: $t = x + 3$. Substitute $t = x + 3$ into the equation for $y$: $y = (x + 3)^2 + 5$. Simplify to get $y = x^2 + 6x + 9 + 5 = x^2 + 6x + 14$.

Eliminate the Parameter x=t−3,y=t2+5x = t - 3 , y = t ^ { 2 } + 5x=t−3,y=t2+5

Eliminate the Parameter $x = t - 3 , y = t ^ { 2 } + 5$