Solve the problem.
-Find the work done by a force $F$ of 20 pounds acting in the direction $\langle 1,5 \rangle$ in moving an object 4 feet from $( 0,0 )$ to $( 4,0 )$.
A) $\approx 35.30$ foot-pounds
B) $\approx 80$ foot-pounds
C) $\approx 15.69$ foot-pounds
D) $\approx 78.45$ foot-pounds

Question

Quizplus · Accepted Answer

The work done is the dot product of the force vector and the displacement vector. The force vector is $20 \cdot \frac{\langle 1,5 \rangle}{\sqrt{1^2 + 5^2}}$ and the displacement vector is $\langle 4,0 \rangle$. The dot product gives approximately 15.69 foot-pounds.

Solve the Problem FFF Of 20 Pounds Acting in the Direction ⟨1,5⟩\langle 1,5 \rangle⟨1,5⟩

Solve the Problem $F$ Of 20 Pounds Acting in the Direction $\langle 1,5 \rangle$