Find the parametrization for the curve.
-The line through the points $( 4,3 )$ and $( 9 , - 3 )$
A) $x = - 10 t - 4 , y = 4 t - 3$
B) $x = 5 t + 4 , y = - 6 t + 3$
C) $x = 5 t + 9 , y = 6 t + 3$
D) $x = - 5 t - 4 , y = 6 t - 3$

Question

Quizplus · Accepted Answer

To find the parametrization of the line through the points $(4,3)$ and $(9,-3)$, we can use the formula $x = x_0 + t\Delta x$ and $y = y_0 + t\Delta y$, where $\Delta x$ and $\Delta y$ are the differences in the x and y coordinates of the two points, respectively, and $(x_0, y_0)$ is one of the points. Here, $\Delta x = 9 - 4 = 5$ and $\Delta y = -3 - 3 = -6$. Using the point $(4,3)$ as $(x_0, y_0)$, we get $x = 4 + 5t$ and $y = 3 - 6t$, which matches choice B.

Find the Parametrization for the Curve (4,3)( 4,3 )(4,3) And (9,−3)( 9 , - 3 )(9,−3)

Find the Parametrization for the Curve $( 4,3 )$ And $( 9 , - 3 )$