Graph $f ( x ) = \left\{ \begin{array} { l c } 4 x + 3 & x

Name: Graph $f ( x ) = \left\{ \begin{array} { l c } 4 x + 3 & x < 0 \\ x + 3 & x \geq 0 \end{array} \right.$ and find the limit of $f ( x )$ as $x$ approaches 0 . A) 15 B) 3 C) 12 D) $- 3$ E) limit does not exist
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Question

Graph $f ( x ) = \left\{ \begin{array} { l c } 4 x + 3 & x < 0 \ x + 3 & x \geq 0 \end{array} \right.$ and find the limit of $f ( x )$ as $x$ approaches 0 .

A) 15 
B) 3 
C) 12 
D) $- 3$ 
E) limit does not exist

Quizplus · Accepted Answer

The Answer of Graph $f ( x ) = \left\{ \begin{array} { l c } 4 x + 3 & x < 0 \ x + 3 & x \geq 0 \end{array} \right.$ and find the limit of $f ( x )$ as $x$ approaches 0 .

A) 15 
B) 3 
C) 12 
D) $- 3$ 
E) limit does not exist

Graph f(x)={4x+3x<0x+3x≥0f ( x ) = \left\{ \begin{array} { l c } 4 x + 3 & x < 0 \\ x + 3 & x \geq 0 \end{array} \right.f(x)={4x+3x+3​x<0x≥0​

Graph $f ( x ) = \left\{ \begin{array} { l c } 4 x + 3 & x < 0 \\ x + 3 & x \geq 0 \end{array} \right.$