Find $\lim _ { x \rightarrow \infty } \frac { 1 - 7 x } { 1 + 9 x }$ (if it exists).
A) 0
B) $- \frac { 7 } { 9 }$
C) $\frac { 7 } { 9 }$
D) $- \infty$
E) limit does not exist

Question

Quizplus · Accepted Answer

To find the limit as $x$ approaches infinity for the given function $\frac{1 - 7x}{1 + 9x}$, we can divide the numerator and the denominator by $x$, the highest power of $x$ in the expression. This simplifies to $\frac{\frac{1}{x} - 7}{\frac{1}{x} + 9}$. As $x$ approaches infinity, $\frac{1}{x}$ approaches 0, leaving us with $\frac{-7}{9}$, which is option B.

Find lim⁡x→∞1−7x1+9x\lim _ { x \rightarrow \infty } \frac { 1 - 7 x } { 1 + 9 x }limx→∞​1+9x1−7x​

Find $\lim _ { x \rightarrow \infty } \frac { 1 - 7 x } { 1 + 9 x }$