Find
$\lim _ { x \rightarrow 7 } \frac { \sqrt { x + 3 } } { x - 3 }$
by direct substitution.
A) $\frac { \sqrt { 7 } } { 4 }$
B) $\frac { \sqrt { 10 } } { 3 }$
C) $\frac { \sqrt { 10 } } { 4 }$
D) $\frac { 1 } { 4 }$
E) $\sqrt { 10 }$

Question

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The Answer of Find
$\lim _ { x \rightarrow 7 } \frac { \sqrt { x + 3 } } { x - 3 }$
by direct substitution.
A) $\frac { \sqrt { 7 } } { 4 }$
B) $\frac { \sqrt { 10 } } { 3 }$
C) $\frac { \sqrt { 10 } } { 4 }$
D) $\frac { 1 } { 4 }$
E) $\sqrt { 10 }$

Find lim⁡x→7x+3x−3\lim _ { x \rightarrow 7 } \frac { \sqrt { x + 3 } } { x - 3 }limx→7​x−3x+3​​

Find $\lim _ { x \rightarrow 7 } \frac { \sqrt { x + 3 } } { x - 3 }$