Find the real solutions, if any, of the equation. Use the quadratic formula.
-$$x ^ { 2 } - 4 x - 7 = 0$$
A) $\{ 4 + \sqrt { 11 } , 4 - \sqrt { 11 } \}$
B) $\{ 2 + \sqrt { 11 } , 2 - \sqrt { 11 } \}$
C) $\{ - 2 + \sqrt { 11 } , - 2 - \sqrt { 11 } \}$
D) $\{ 2 + \sqrt { 7 } , 2 - \sqrt { 7 } \}$

Question

Quizplus · Accepted Answer

The quadratic formula is $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$. For the equation $x^2 - 4x - 7 = 0$, $a = 1$, $b = -4$, and $c = -7$. Plugging these into the formula gives $x = \frac{4 \pm \sqrt{16 + 28}}{2} = \frac{4 \pm \sqrt{44}}{2} = \frac{4 \pm 2\sqrt{11}}{2} = 2 \pm \sqrt{11}$.

Find the Real Solutions, If Any, of the Equation x2−4x−7=0x ^ { 2 } - 4 x - 7 = 0x2−4x−7=0

Find the Real Solutions, If Any, of the Equation $x ^ { 2 } - 4 x - 7 = 0$