Solve the equation by completing the square.
-$$x ^ { 2 } - 12 x - 5 = 0$$
A) $\{ 12 - \sqrt { 149 } , 12 + \sqrt { 149 } \}$
B) $\{ 6 - \sqrt { 41 } , 6 + \sqrt { 41 } \}$
C) $\{ - 6 - \sqrt { 41 } , - 6 + \sqrt { 41 } \}$
D) $\{ 6 - \sqrt { 5 } , 6 + \sqrt { 5 } \}$

Question

Quizplus · Accepted Answer

To complete the square, rewrite the equation as $(x - 6)^2 = 41$. Solving gives $x = 6 \pm \sqrt{41}$.

Solve the Equation by Completing the Square x2−12x−5=0x ^ { 2 } - 12 x - 5 = 0x2−12x−5=0

Solve the Equation by Completing the Square $x ^ { 2 } - 12 x - 5 = 0$