Find the real solutions, if any, of the equation. Use the quadratic formula.
-$16 x ^ { 2 } - 64 x + 64 = 0$
A) no real solution
B) $\{ 2 , - 32 \}$
C) $\{ - 2 \}$
D) $\{ 2 \}$

Question

Quizplus · Accepted Answer

The quadratic formula is $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 16$, $b = -64$, and $c = 64$. Plugging these values in, we get $x = \frac{64 \pm \sqrt{(-64)^2 - 4(16)(64)}}{2(16)} = \frac{64 \pm \sqrt{4096 - 4096}}{32} = \frac{64}{32} = 2$, indicating a single real solution, which is $x = 2$.

Find the Real Solutions, If Any, of the Equation 16x2−64x+64=016 x ^ { 2 } - 64 x + 64 = 016x2−64x+64=0

Find the Real Solutions, If Any, of the Equation $16 x ^ { 2 } - 64 x + 64 = 0$