An inductor has a current I = 0.5A cos[( 275 s^-1) t] . The maximum emf across the inductor is equal to 0.5 V. What is the self-inductance of the inductor? A)4.37 mH B)3.64 mH C)2.75 mH D)0.73 mH E)1.43 mH

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Quizplus · Accepted Answer

The maximum emf (E) across an inductor is given by E = L * ω * I_max, where L is the inductance, ω is the angular frequency, and I_max is the maximum current. Here, I_max = 0.5 A, ω = 275 s^-1, and E = 0.5 V. Solving for L gives L = E / (ω * I_max) = 0.5 / (275 * 0.5) = 3.64 mH.

An Inductor Has a Current I = 0