A coil with a self-inductance of 6.0 H is connected to a dc source through a switch. As soon as the switch is closed at t = 0 s, the rate of change of current is 2.0 A/s. What is the emf induced in this coil at t = 0 s?
A)6.0 V
B)3.0 V
C)12 V
D)0.33 V
E)0 V

Question

Quizplus · Accepted Answer

The emf induced in the coil can be calculated using the formula: emf = -L * (di/dt), where L is the self-inductance and di/dt is the rate of change of current. Substituting the given values, emf = -6.0 H * 2.0 A/s = -12 V. The negative sign indicates the direction of the induced emf, but the magnitude is 12 V.

A Coil with a Self-Inductance of 6