A solenoid of length 5.0 cm has a cross sectional area of 1.0 cm² and has 300 uniformly spaced turns. The solenoid is wrapped in 180 turns of insulated wire resulting in a mutual inductance of A)1.1 H. B)1.4 × 10^-2 H. C)11 H. D)1.4 × 10^-4 H. E)110 H.

Question

Quizplus · Accepted Answer

The mutual inductance M can be calculated using the formula M = (μ₀ * N₁ * N₂ * A) / l, where μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A), N₁ and N₂ are the number of turns in the solenoid and the wire respectively, A is the cross-sectional area, and l is the length of the solenoid. Substituting the given values results in M ≈ 1.4 × 10⁻⁴ H.

A Solenoid of Length 5