Factor using the ac-method.
-$x ^ { 5 } - 2 x ^ { 4 } - 8 x ^ { 3 }$
A) $x ^ { 3 } ( x + 4 ) ( x + 2 )$
B) $x ^ { 3 } ( x - 4 ) ( x + 2 )$
C) $x ^ { 3 } ( x - 4 ) ( x - 2 )$
D) $x ^ { - 4 } \left( x ^ { 2 } - 2 x - 8 \right)$

Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is $x^3$, to get $x^3(x^2 - 2x - 8)$. Then, factor the quadratic $x^2 - 2x - 8$ to get $(x - 4)(x + 2)$. Therefore, the correct factorization is $x^3(x - 4)(x + 2)$.

Factor Using the Ac-Method x5−2x4−8x3x ^ { 5 } - 2 x ^ { 4 } - 8 x ^ { 3 }x5−2x4−8x3

Factor Using the Ac-Method $x ^ { 5 } - 2 x ^ { 4 } - 8 x ^ { 3 }$