Factor using the ac-method.
-$18 - 9 x + x ^ { 2 }$
A) $( x - 6 ) ( x - 3 )$
B) $( x + 6 ) ( x - 3 )$
C) $( x + 6 ) ( x + 3 )$
D) $( x - 6 ) ( x + 3 )$

Question

Quizplus · Accepted Answer

The correct factorization of $18 - 9x + x^2$ is $(x - 6)(x - 3)$. This is found by rearranging the equation to $x^2 - 9x + 18$ and then finding two numbers that multiply to $18$ (the constant term) and add to $-9$ (the coefficient of $x$), which are $-6$ and $-3$.

Factor Using the Ac-Method 18−9x+x218 - 9 x + x ^ { 2 }18−9x+x2

Factor Using the Ac-Method $18 - 9 x + x ^ { 2 }$