Factor using the ac-method.
-$6 y ^ { 4 } + 5 y ^ { 2 } - 6$
A) $\left( 6 y ^ { 2 } - 2 \right) \left( y ^ { 2 } + 3 \right)$
B) $\left( 3 y ^ { 2 } + 1 \right) \left( 2 y ^ { 2 } - 6 \right)$
C) $( 2 y - 3 ) ( 3 y + 2 )$
D) $\left( 3 y ^ { 2 } - 2 \right) \left( 2 y ^ { 2 } + 3 \right)$

Question

Quizplus · Accepted Answer

The ac-method involves multiplying the leading coefficient (6) by the constant term (-6) to get -36. We then find two numbers that multiply to -36 and add to 5, which are 9 and -4. Rewriting the middle term, we factor by grouping to get $(3y^2 - 2)(2y^2 + 3)$.

Factor Using the Ac-Method 6y4+5y2−66 y ^ { 4 } + 5 y ^ { 2 } - 66y4+5y2−6

Factor Using the Ac-Method $6 y ^ { 4 } + 5 y ^ { 2 } - 6$