Factor using the ac-method.
-$6 x ^ { 2 } - 7 x t - 3 t ^ { 2 }$
A) $( 3 x + t ) ( 2 x - 3 t )$
B) prime
C) $( 3 x - t ) ( 2 x + 3 t )$
D) $( 6 x + t ) ( x - 3 t )$

Question

Quizplus · Accepted Answer

The correct factorization of $6x^2 - 7xt - 3t^2$ is achieved by finding two numbers that multiply to $ac = 6(-3) = -18$ and add to $b = -7$. The numbers -9 and 2 fit this criterion. Rewriting the middle term: $6x^2 - 9xt + 2xt - 3t^2$, and factoring by grouping gives $(3x + t)(2x - 3t)$.

Factor Using the Ac-Method 6x2−7xt−3t26 x ^ { 2 } - 7 x t - 3 t ^ { 2 }6x2−7xt−3t2

Factor Using the Ac-Method $6 x ^ { 2 } - 7 x t - 3 t ^ { 2 }$