Factor.
-$18 z ^ { 6 } - 15 z ^ { 4 } - 18 z ^ { 2 }$
A) $\left( 6 z ^ { 3 } - 9 \right) \left( 3 z ^ { 3 } + 2 \right)$
B) $3 z ^ { 2 } \left( 2 z ^ { 2 } - 3 \right) \left( 3 z ^ { 2 } + 2 \right)$
C) $3 \left( 2 z ^ { 4 } - 3 \right) \left( 3 z ^ { 2 } + 2 \right)$
D) $3 z ^ { 2 } \left( 3 z ^ { 2 } - 2 \right) \left( 2 z ^ { 2 } + 3 \right)$

Question

Quizplus · Accepted Answer

The greatest common factor of the terms $18z^6$, $-15z^4$, and $-18z^2$ is $3z^2$. Factoring $3z^2$ out, we get $3z^2(6z^4 - 5z^2 - 6)$. Factoring the quadratic expression in parentheses further, we find it factors into $(2z^2 - 3)(3z^2 + 2)$, leading to the correct factorization as $3z^2(2z^2 - 3)(3z^2 + 2)$.

Factor - 18z6−15z4−18z218 z ^ { 6 } - 15 z ^ { 4 } - 18 z ^ { 2 }18z6−15z4−18z2

Factor
- $18 z ^ { 6 } - 15 z ^ { 4 } - 18 z ^ { 2 }$