Factor.
-$$3 a ^ { 3 } + 12 a ^ { 2 } - 15 a$$
A) $3 a ( a - 5 ) ( a - 1 )$
B) $3 a ( a + 5 ) ( a - 1 )$
C) $3 a ( a + 5 ) ( a + 1 )$
D) $3 a ( a - 5 ) ( a + 1 )$

Question

Quizplus · Accepted Answer

The expression can be factored by first taking out the greatest common factor, 3a, resulting in $3a(a^2 + 4a - 5)$. The quadratic $a^2 + 4a - 5$ factors into $(a + 5)(a - 1)$, giving the final factorization $3a(a + 5)(a - 1)$.

Factor - 3a3+12a2−15a3 a ^ { 3 } + 12 a ^ { 2 } - 15 a3a3+12a2−15a

Factor
- $3 a ^ { 3 } + 12 a ^ { 2 } - 15 a$