Factor.
-$8 z ^ { 3 } - 6 z ^ { 2 } - 9 z$
A) $z ( 4 z + 3 ) ( 2 z - 3 )$
B) $z ( 8 z + 1 ) ( z - 9 )$
C) $( 4 z - 3 ) ( 2 z + 3 )$
D) $\left( z ^ { 2 } - 3 \right) ( 8 z + 3 )$

Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is $z$, giving $z(8z^2 - 6z - 9)$. Then, factor the quadratic expression inside the parentheses to get $z(4z + 3)(2z - 3)$.

Factor - 8z3−6z2−9z8 z ^ { 3 } - 6 z ^ { 2 } - 9 z8z3−6z2−9z

Factor
- $8 z ^ { 3 } - 6 z ^ { 2 } - 9 z$