Solve the system.
-$\left\{ \begin{array} { r r }
y + 4 z & = 18 \
2 x + y - 2 z & = - 12 \
- 4 x - 2 z & = 4
\end{array} \right.$
A) $( - 5,14,8 )$
B) $( - 3 , - 2,5 )$
C) $( - 3,2,4 )$
D) $( - 5,3,8 )$

Question

Solve the system.
-$\left\{ \begin{array} { r r } 
y + 4 z & = 18 \
2 x + y - 2 z & = - 12 \
- 4 x - 2 z & = 4
\end{array} \right.$
A) $( - 5,14,8 )$
B) $( - 3 , - 2,5 )$
C) $( - 3,2,4 )$
D) $( - 5,3,8 )$

Quizplus · Accepted Answer

To solve the system, we can use substitution or elimination. The third equation can be simplified to $2x + z = -2$. We can solve this system by substituting the values from one equation into the others and solving for the variables. After solving, we find that the solution is $(-3, 2, 4)$, which matches choice C.

Solve the System {y+4z=182x+y−2z=−12−4x−2z=4\left\{ \begin{array} { r r } y + 4 z & = 18 \\2 x + y - 2 z & = - 12 \\- 4 x - 2 z & = 4\end{array} \right.⎩⎨⎧​y+4z2x+y−2z−4x−2z​=18=−12=4​

Solve the System $\left\{ \begin{array} { r r } y + 4 z & = 18 \\2 x + y - 2 z & = - 12 \\- 4 x - 2 z & = 4\end{array} \right.$