Although $( 1,10 )$ is not a solution of $x + 5 y = 2$, it can still be a solution of the system $\left\{ \begin{array} { l } x + 5 y = 2 \ x + y = 2 \end{array} \right.$.

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For a point to be a solution of a system of equations, it must satisfy all equations in the system. If $(1,10)$ does not satisfy one of the equations, it cannot be a solution to the system.

Although (1,10)( 1,10 )(1,10) Is Not a Solution Of x+5y=2x + 5 y = 2x+5y=2

Although $( 1,10 )$ Is Not a Solution Of $x + 5 y = 2$