Solve the system of equations by the addition method.
-$\left\{ \begin{array} { l }
x + y = 23 \
x - y = 15
\end{array} \right.$
A) no solution
B) $( 19,4 )$
C) $( 4,19 )$
D) $\left( \frac { 23 } { 2 } , \frac { 15 } { 2 } \right)$

Question

Solve the system of equations by the addition method.
-$\left\{ \begin{array} { l } 
x + y = 23 \
x - y = 15
\end{array} \right.$
A) no solution
B) $( 19,4 )$
C) $( 4,19 )$
D) $\left( \frac { 23 } { 2 } , \frac { 15 } { 2 } \right)$

Quizplus · Accepted Answer

Adding the two equations $x + y = 23$ and $x - y = 15$ eliminates $y$, giving $2x = 38$, which simplifies to $x = 19$. Substituting $x = 19$ into the first equation gives $19 + y = 23$, leading to $y = 4$. Therefore, the solution is $(19, 4)$.

Solve the System of Equations by the Addition Method {x+y=23x−y=15\left\{ \begin{array} { l } x + y = 23 \\x - y = 15\end{array} \right.{x+y=23x−y=15​

Solve the System of Equations by the Addition Method $\left\{ \begin{array} { l } x + y = 23 \\x - y = 15\end{array} \right.$