Factor the binomial completely.
-$49 y ^ { 2 } - ( x + 3 ) ^ { 2 }$
A) $( 7 y + 3 x ) ( 7 y - 3 x )$
B) $( 7 y + x + 3 ) ( 7 y - x + 3 )$
C) $( 7 y - x - 3 ) ^ { 2 }$
D) $( 7 y + x + 3 ) ( 7 y - x - 3 )$

Question

Quizplus · Accepted Answer

The expression is a difference of squares: $ (7y)^2 - (x+3)^2 $. It factors as $(7y + (x+3))(7y - (x+3))$, which simplifies to $(7y + x + 3)(7y - x - 3)$.

Factor the Binomial Completely 49y2−(x+3)249 y ^ { 2 } - ( x + 3 ) ^ { 2 }49y2−(x+3)2

Factor the Binomial Completely $49 y ^ { 2 } - ( x + 3 ) ^ { 2 }$