Factor the sum or difference of two cubes.
-$64 p ^ { 3 } - 1$
A) $( 4 p - 1 ) \left( 16 p ^ { 2 } + 1 \right)$
B) $( 64 p - 1 ) \left( p ^ { 2 } + 4 p + 1 \right)$
C) $( 4 p - 1 ) \left( 16 p ^ { 2 } + 4 p + 1 \right)$
D) $( 4 p + 1 ) \left( 16 p ^ { 2 } - 4 p + 1 \right)$

Question

Quizplus · Accepted Answer

The sum or difference of two cubes can be factored using the formula $a^3 - b^3 = (a - b)(a^2 + ab + b^2)$. Here, $64p^3 = (4p)^3$ and $1 = 1^3$, so the factored form is $(4p - 1)(16p^2 + 4p + 1)$.

Factor the Sum or Difference of Two Cubes 64p3−164 p ^ { 3 } - 164p3−1

Factor the Sum or Difference of Two Cubes $64 p ^ { 3 } - 1$