Factor the binomial completely.
-$x ^ { 2 } - \frac { 16 } { 49 }$
A) $\left( x + \frac { 4 } { 7 } \right) ^ { 2 }$
B) $\left( x - \frac { 4 } { 7 } \right) ^ { 2 }$
C) $\left( x + \frac { 4 } { 7 } \right) \left( \frac { 4 } { 7 } - x \right)$
D) $\left( x + \frac { 4 } { 7 } \right) \left( x - \frac { 4 } { 7 } \right)$

Question

Quizplus · Accepted Answer

The binomial $x^2 - \frac{16}{49}$ is a difference of squares, which factors into $\left( x + \frac{4}{7} \right) \left( x - \frac{4}{7} \right)$.

Factor the Binomial Completely x2−1649x ^ { 2 } - \frac { 16 } { 49 }x2−4916​

Factor the Binomial Completely $x ^ { 2 } - \frac { 16 } { 49 }$