Solve the problem.
-Find the area of a triangular-shaped field with sides of $244.5 \mathrm {~m}$ and $163.9 \mathrm {~m}$, and the included angle between them measuring $64.65 ^ { \circ }$. Round to the nearest square meter.
A) $36,215 \mathrm {~m} ^ { 2 }$
B) $17,157 \mathrm {~m} ^ { 2 }$
C) $18,107 \mathrm {~m} ^ { 2 }$
D) $8579 \mathrm {~m} ^ { 2 }$

Question

Quizplus · Accepted Answer

The area of a triangle with two sides $a$ and $b$ and an included angle $\theta$ is given by $\frac{1}{2}ab\sin(\theta)$. Substituting the given values, the area is approximately $18,107 \mathrm {~m} ^ { 2 }$.

Solve the Problem 244.5 m244.5 \mathrm {~m}244.5 m And 163.9 m163.9 \mathrm {~m}163.9 m , and the Included Angle Between Them Measuring

Solve the Problem $244.5 \mathrm {~m}$ And $163.9 \mathrm {~m}$ , and the Included Angle Between Them Measuring