Find the area of triangle ABC with the given parts. Round to the nearest tenth when necessary.
-$$\begin{array} { l }
\mathrm { A } = 38.1 ^ { \circ } \
\mathrm { b } = 12.0 \mathrm { in } . \
\mathrm { c } = 5.5 \mathrm { in } .
\end{array}$$
A) $18.4$ in. $^ { 2 }$
B) 26 in. 2
C) 28 in. 2
D) $20.4$ in. ${ } ^ { 2 }$

Question

Find the area of triangle ABC with the given parts. Round to the nearest tenth when necessary.
-$$\begin{array} { l } 
\mathrm { A } = 38.1 ^ { \circ } \
\mathrm { b } = 12.0 \mathrm { in } . \
\mathrm { c } = 5.5 \mathrm { in } .
\end{array}$$
A) $18.4$ in. $^ { 2 }$
B) 26 in. 2
C) 28 in. 2
D) $20.4$ in. ${ } ^ { 2 }$

Quizplus · Accepted Answer

To find the area of triangle ABC, we can use the formula for the area of a triangle given two sides and an included angle: $$Area = \frac{1}{2}bc\sin(A)$$ where $b = 12.0$ in, $c = 5.5$ in, and $A = 38.1^\circ$. Plugging in the values: $$Area = \frac{1}{2} \times 12.0 \times 5.5 \times \sin(38.1^\circ)$$ Calculating this gives an area of approximately $20.4$ square inches, rounding to the nearest tenth.

Find the Area of Triangle ABC with the Given Parts A=38.1∘b=12.0in.c=5.5in.\begin{array} { l } \mathrm { A } = 38.1 ^ { \circ } \\\mathrm { b } = 12.0 \mathrm { in } . \\\mathrm { c } = 5.5 \mathrm { in } .\end{array}A=38.1∘b=12.0in.c=5.5in.​

Find the Area of Triangle ABC with the Given Parts $\begin{array} { l } \mathrm { A } = 38.1 ^ { \circ } \\\mathrm { b } = 12.0 \mathrm { in } . \\\mathrm { c } = 5.5 \mathrm { in } .\end{array}$