Find the area of triangle ABC with the given parts. Round to the nearest tenth when necessary.
-$$\begin{array} { l }
\mathrm { A } = 41 ^ { \circ } 20 ^ { \prime } \
\mathrm { b } = 17.6 \mathrm {~m} \
\mathrm { c } = 9.2 \mathrm {~m}
\end{array}$$
A) $53.5 \mathrm {~m} ^ { 2 }$
B) $26.8 \mathrm {~m} ^ { 2 }$
C) $109 \mathrm {~m} ^ { 2 }$
D) $107 \mathrm {~m} ^ { 2 }$

Question

Find the area of triangle ABC with the given parts. Round to the nearest tenth when necessary.
-$$\begin{array} { l } 
\mathrm { A } = 41 ^ { \circ } 20 ^ { \prime } \
\mathrm { b } = 17.6 \mathrm {~m} \
\mathrm { c } = 9.2 \mathrm {~m}
\end{array}$$
A) $53.5 \mathrm {~m} ^ { 2 }$
B) $26.8 \mathrm {~m} ^ { 2 }$
C) $109 \mathrm {~m} ^ { 2 }$
D) $107 \mathrm {~m} ^ { 2 }$

Quizplus · Accepted Answer

The area of the triangle can be found using the formula: $\text{Area} = \frac{1}{2}bc\sin(A)$. Substituting the given values: $\text{Area} = \frac{1}{2} \times 17.6 \times 9.2 \times \sin(41^\circ 20')$. Calculating this gives approximately $53.5 \mathrm {~m} ^ { 2 }$.

Find the Area of Triangle ABC with the Given Parts