Solve the system by substitution.
-$$\begin{array} { l }
4 x - 10 y = 5 \
4 x + 10 y = 5
\end{array}$$
A) $\left\{ \left( \frac { 5 } { 4 } , 0 \right) \right\}$
B) $\left\{ \left( 0 , \frac { 4 } { 5 } \right) \right\}$
C) $\varnothing$
D) $\left\{ \left( \frac { 5 } { 4 } , 1 \right) \right\}$

Question

Solve the system by substitution.
-$$\begin{array} { l } 
4 x - 10 y = 5 \
4 x + 10 y = 5
\end{array}$$
A) $\left\{ \left( \frac { 5 } { 4 } , 0 \right) \right\}$
B) $\left\{ \left( 0 , \frac { 4 } { 5 } \right) \right\}$
C) $\varnothing$
D) $\left\{ \left( \frac { 5 } { 4 } , 1 \right) \right\}$

Quizplus · Accepted Answer

Adding the two equations cancels out $y$, leading to $8x = 10$, which simplifies to $x = \frac{5}{4}$. Substituting $x = \frac{5}{4}$ into either equation shows $y = 0$, making the solution $\left\{ \left( \frac { 5 } { 4 } , 0 \right) \right\}$.

Solve the System by Substitution 4x−10y=54x+10y=5\begin{array} { l } 4 x - 10 y = 5 \\4 x + 10 y = 5\end{array}4x−10y=54x+10y=5​

Solve the System by Substitution $\begin{array} { l } 4 x - 10 y = 5 \\4 x + 10 y = 5\end{array}$