Verify that the values of the variables listed are solutions of the system of equations.
-$$\begin{array} { l }
\left\{ \begin{array} { l }
x + y = 8 \
x - y = 4
\end{array} \right. \
x = 6 , y = 2
\end{array}$$
A) not a solution
B) solution

Question

Verify that the values of the variables listed are solutions of the system of equations.
-$$\begin{array} { l } 
\left\{ \begin{array} { l } 
x + y = 8 \
x - y = 4
\end{array} \right. \
x = 6 , y = 2
\end{array}$$
A) not a solution
B) solution

Quizplus · Accepted Answer

Substituting $x = 6$ and $y = 2$ into both equations: For the first equation, $6 + 2 = 8$ which is true. For the second equation, $6 - 2 = 4$ which is also true. Therefore, $x = 6$ and $y = 2$ satisfy both equations, making them a solution to the system.

Verify That the Values of the Variables Listed Are Solutions {x+y=8x−y=4x=6,y=2\begin{array} { l } \left\{ \begin{array} { l } x + y = 8 \\x - y = 4\end{array} \right. \\x = 6 , y = 2\end{array}{x+y=8x−y=4​x=6,y=2​

Verify That the Values of the Variables Listed Are Solutions $\begin{array} { l } \left\{ \begin{array} { l } x + y = 8 \\x - y = 4\end{array} \right. \\x = 6 , y = 2\end{array}$