Solve the system of equations by using substitution.
-$$\left\{ \begin{array} { l }
5 x + 3 y = 80 \
2 x + y = 30
\end{array} \right.$$
A) x = 0, y = 0
B) x = 10, y = 10
C) x = 0, y = 10
D) x = 10, y = 0

Question

Solve the system of equations by using substitution.
-$$\left\{ \begin{array} { l } 
5 x + 3 y = 80 \
2 x + y = 30
\end{array} \right.$$
A) x = 0, y = 0
B) x = 10, y = 10
C) x = 0, y = 10
D) x = 10, y = 0

Quizplus · Accepted Answer

From the second equation, $y = 30 - 2x$. Substituting this into the first equation gives $5x + 3(30 - 2x) = 80$, which simplifies to $5x + 90 - 6x = 80$, leading to $-x = -10$, so $x = 10$. Substituting $x = 10$ back into $y = 30 - 2x$ gives $y = 30 - 20 = 10$.

Solve the System of Equations by Using Substitution {5x+3y=802x+y=30\left\{ \begin{array} { l } 5 x + 3 y = 80 \\2 x + y = 30\end{array} \right.{5x+3y=802x+y=30​

Solve the System of Equations by Using Substitution $\left\{ \begin{array} { l } 5 x + 3 y = 80 \\2 x + y = 30\end{array} \right.$