Solve the system of equations by using substitution.
-$$\left\{ \begin{array} { l }
3 x + y = 13 \
2 x + 9 y = - 8
\end{array} \right.$$
A) x = 5, y = 2
B) x = -5, y = 2
C) x = 5, y = -2
D) x = -5, y = -2

Question

Solve the system of equations by using substitution.
-$$\left\{ \begin{array} { l } 
3 x + y = 13 \
2 x + 9 y = - 8
\end{array} \right.$$
A) x = 5, y = 2
B) x = -5, y = 2
C) x = 5, y = -2
D) x = -5, y = -2

Quizplus · Accepted Answer

First, solve the first equation for y: $ y = 13 - 3x $. Substitute this expression for y in the second equation: $ 2x + 9(13 - 3x) = -8 $. Simplify and solve for x: $ 2x + 117 - 27x = -8 $, which simplifies to $ -25x = -125 $, giving $ x = 5 $. Substitute $ x = 5 $ back into $ y = 13 - 3x $ to find $ y = -2 $. Thus, the solution is $ x = 5, y = -2 $.

Solve the System of Equations by Using Substitution {3x+y=132x+9y=−8\left\{ \begin{array} { l } 3 x + y = 13 \\2 x + 9 y = - 8\end{array} \right.{3x+y=132x+9y=−8​

Solve the System of Equations by Using Substitution $\left\{ \begin{array} { l } 3 x + y = 13 \\2 x + 9 y = - 8\end{array} \right.$