Solve for the indicated variable.
-$\log _ { c } ( z + s ) = \log _ { c } ( 2 z - 4 )$, for $s$
A) $s = \frac { z } { 4 }$
B) $s = \frac { \log _ { c } z } { 4 }$
C) $s = z - 4$
D) $s = \log _ { c } ( z - 4 )$

Question

Quizplus · Accepted Answer

Given $\log_c(z + s) = \log_c(2z - 4)$, since the bases of the logarithms are the same, the arguments must be equal. Therefore, $z + s = 2z - 4$. Solving for $s$, we subtract $z$ from both sides to get $s = z - 4$.

Solve for the Indicated Variable log⁡c(z+s)=log⁡c(2z−4)\log _ { c } ( z + s ) = \log _ { c } ( 2 z - 4 )logc​(z+s)=logc​(2z−4)

Solve for the Indicated Variable $\log _ { c } ( z + s ) = \log _ { c } ( 2 z - 4 )$