Solve the equation and express the solution in exact form.
-$$\log _ { 2 } \sqrt { 2 x ^ { 2 } } = \frac { 11 } { 2 }$$
A) $\{ - 16,16 \}$
B) $\{ 32 \}$
C) $\{ - 32,32 \}$
D) $\{ - 1024,1024 \}$

Question

Quizplus · Accepted Answer

The equation simplifies to $ \log_2 |x| = \frac{11}{2} $, which means $ |x| = 2^{\frac{11}{2}} = 32 $. Thus, $ x = \pm 32 $.

Solve the Equation and Express the Solution in Exact Form log⁡22x2=112\log _ { 2 } \sqrt { 2 x ^ { 2 } } = \frac { 11 } { 2 }log2​2x2​=211​

Solve the Equation and Express the Solution in Exact Form $\log _ { 2 } \sqrt { 2 x ^ { 2 } } = \frac { 11 } { 2 }$