Solve for the indicated variable.
-$\mathrm { T } = \mathrm { T } _ { 0 } \mathrm { e } ^ { \mathrm { kt } / 300 }$, for $\mathrm { t }$
A) $t = \frac { k } { 300 } \ln \frac { T } { T _ { 0 } }$
B) $t = \frac { 300 } { k } \ln \left( T - T _ { 0 } \right)$
C) $t = \frac { 300 \mathrm {~T} } { \mathrm { kT } _ { 0 } }$
D) $t = \frac { 300 } { k } \ln \frac { T } { T _ { 0 } }$

Question

Quizplus · Accepted Answer

To solve for $t$, divide both sides by $T_0$, then take the natural logarithm of both sides to get rid of the exponential, resulting in $t = \frac{300}{k} \ln \frac{T}{T_0}$.

Solve for the Indicated Variable T=T0ekt/300\mathrm { T } = \mathrm { T } _ { 0 } \mathrm { e } ^ { \mathrm { kt } / 300 }T=T0​ekt/300

Solve for the Indicated Variable $\mathrm { T } = \mathrm { T } _ { 0 } \mathrm { e } ^ { \mathrm { kt } / 300 }$