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Tech: Conic Sections in Polar Coordinates
- $r=\frac{2}{2+2 \sin \left(\theta+\frac{\pi}{6}\right)}$ A)

B)

C)

D)

Question 224

Multiple Choice

Tech: Conic Sections in Polar Coordinates
- $r=\frac{2}{2+2 \sin \left(\theta+\frac{\pi}{6}\right) }$
$Tech: Conic Sections in Polar Coordinates - r=\frac{2}{2+2 \sin \left(\theta+\frac{\pi}{6}\right) } A) B) C) D)$

A)
$Tech: Conic Sections in Polar Coordinates - r=\frac{2}{2+2 \sin \left(\theta+\frac{\pi}{6}\right) } A) B) C) D)$
B)
$Tech: Conic Sections in Polar Coordinates - r=\frac{2}{2+2 \sin \left(\theta+\frac{\pi}{6}\right) } A) B) C) D)$
C)
$Tech: Conic Sections in Polar Coordinates - r=\frac{2}{2+2 \sin \left(\theta+\frac{\pi}{6}\right) } A) B) C) D)$
D)
$Tech: Conic Sections in Polar Coordinates - r=\frac{2}{2+2 \sin \left(\theta+\frac{\pi}{6}\right) } A) B) C) D)$