Solve the problem.
-$$\frac { - 32 x ^ { 8 } - 32 x ^ { 6 } - 56 x ^ { 4 } } { - 8 x ^ { 6 } }$$
A) $4 x + 4 + \frac { 7 } { x ^ { 2 } }$
B) $4 x ^ { 2 } + 4 + \frac { 7 } { x }$
C) $4 x + 4 + \frac { 7 } { x }$
D) $4 x ^ { 2 } + 4 + \frac { 7 } { x ^ { 2 } }$

Question

Quizplus · Accepted Answer

Dividing each term in the numerator by the denominator gives: $\frac{-32x^8}{-8x^6} = 4x^2$, $\frac{-32x^6}{-8x^6} = 4$, and $\frac{-56x^4}{-8x^6} = \frac{7}{x^2}$.

Solve the Problem −32x8−32x6−56x4−8x6\frac { - 32 x ^ { 8 } - 32 x ^ { 6 } - 56 x ^ { 4 } } { - 8 x ^ { 6 } }−8x6−32x8−32x6−56x4​

Solve the Problem $\frac { - 32 x ^ { 8 } - 32 x ^ { 6 } - 56 x ^ { 4 } } { - 8 x ^ { 6 } }$