Solve the problem.
-$$\frac { - 8 x ^ { 10 } + 40 x ^ { 6 } } { - 4 x ^ { 2 } }$$
A) $2 x ^ { 8 } - 10 x ^ { 4 }$
B) $- 8 x ^ { 10 } - 10 x ^ { 4 }$
C) $- 8 x ^ { 14 }$
D) $2 x ^ { 8 } + 40 x ^ { 6 }$

Name: Solve the problem. -\[\frac { - 8 x ^ { 10 } + 40 x ^ { 6 } } { - 4 x ^ { 2 } }\] A) $2 x ^ { 8 } - 10 x ^ { 4 }$ B) $- 8 x ^ { 10 } - 10 x ^ { 4 }$ C) $- 8 x ^ { 14 }$ D) $2 x ^ { 8 } + 40 x ^ { 6 }$
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Question

Quizplus · Accepted Answer

Dividing each term in the numerator by the term in the denominator gives $2x^{8} - 10x^{4}$.

Solve the Problem −8x10+40x6−4x2\frac { - 8 x ^ { 10 } + 40 x ^ { 6 } } { - 4 x ^ { 2 } }−4x2−8x10+40x6​

Solve the Problem $\frac { - 8 x ^ { 10 } + 40 x ^ { 6 } } { - 4 x ^ { 2 } }$