Solve the equation
-$$\frac { x ^ { 2 } + 3 x - 40 } { x + 8 }$$
A) $x ^ { 2 } + 4 x - 32$
B) $x ^ { 2 } - 5$
C) $x - 5$
D) $x + 5$

Name: Solve the equation -\[\frac { x ^ { 2 } + 3 x - 40 } { x + 8 }\] A) $x ^ { 2 } + 4 x - 32$ B) $x ^ { 2 } - 5$ C) $x - 5$ D) $x + 5$
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Question

Quizplus · Accepted Answer

The given expression can be simplified by factoring the numerator as follows: $\frac{x^2 + 3x - 40}{x + 8} = \frac{(x + 8)(x - 5)}{x + 8}$. When we cancel out the $x + 8$ terms, we are left with $x - 5$, which corresponds to option C.

Solve the Equation - x2+3x−40x+8\frac { x ^ { 2 } + 3 x - 40 } { x + 8 }x+8x2+3x−40​

Solve the Equation
- $\frac { x ^ { 2 } + 3 x - 40 } { x + 8 }$