Solve the system of equations by elimination, if a solution exists.
-$$\left\{ \begin{array} { l }
x - 6 y = - 30 \
- 5 x - 5 y = - 25
\end{array} \right.$$
A) $x = - 5 , y = 0$
B) No solution
C) $x = 1 , y = 4$
D) $x = 0 , y = 5$

Question

Solve the system of equations by elimination, if a solution exists.
-$$\left\{ \begin{array} { l } 
x - 6 y = - 30 \
- 5 x - 5 y = - 25
\end{array} \right.$$
A) $x = - 5 , y = 0$
B) No solution
C) $x = 1 , y = 4$
D) $x = 0 , y = 5$

Quizplus · Accepted Answer

By multiplying the first equation by 5 and adding it to the second equation, we eliminate $x$ and find $y = 5$. Substituting $y = 5$ back into the first equation gives $x = 0$.

Solve the System of Equations by Elimination, If a Solution {x−6y=−30−5x−5y=−25\left\{ \begin{array} { l } x - 6 y = - 30 \\- 5 x - 5 y = - 25\end{array} \right.{x−6y=−30−5x−5y=−25​

Solve the System of Equations by Elimination, If a Solution $\left\{ \begin{array} { l } x - 6 y = - 30 \\- 5 x - 5 y = - 25\end{array} \right.$