Solve the system of equations by elimination, if a solution exists.
-$$\left\{ \begin{array} { l }
6 x - 3 y = - 5 \
18 x - 9 y = 15
\end{array} \right.$$
A) $x = 30 , y = - 15$
B) $x = 0 , y = 0$
C) $x = - 30 , y = 15$
D) No solution

Question

Solve the system of equations by elimination, if a solution exists.
-$$\left\{ \begin{array} { l } 
6 x - 3 y = - 5 \
18 x - 9 y = 15
\end{array} \right.$$
A) $x = 30 , y = - 15$
B) $x = 0 , y = 0$
C) $x = - 30 , y = 15$
D) No solution

Quizplus · Accepted Answer

The second equation is a multiple of the first (multiplied by 3). This means the two equations are essentially the same line, and thus, they do not intersect at a single point. This results in an infinite number of solutions, which is best represented by the choice indicating no single solution exists.

Solve the System of Equations by Elimination, If a Solution {6x−3y=−518x−9y=15\left\{ \begin{array} { l } 6 x - 3 y = - 5 \\18 x - 9 y = 15\end{array} \right.{6x−3y=−518x−9y=15​

Solve the System of Equations by Elimination, If a Solution $\left\{ \begin{array} { l } 6 x - 3 y = - 5 \\18 x - 9 y = 15\end{array} \right.$