Solve the system of equations by substitution, if a solution exists.
-$$\left\{ \begin{array} { l }
5 x + 9 y = 36 \
3 x + 5 y = 20
\end{array} \right.$$
A) No Solution
B) $x = 0 , y = 4$
C) $x = - 1 , y = 5$
D) $x = 0 , y = 5$

Question

Solve the system of equations by substitution, if a solution exists.
-$$\left\{ \begin{array} { l } 
5 x + 9 y = 36 \
3 x + 5 y = 20
\end{array} \right.$$
A) No Solution
B) $x = 0 , y = 4$
C) $x = - 1 , y = 5$
D) $x = 0 , y = 5$

Quizplus · Accepted Answer

To solve the system by substitution, we can solve one of the equations for one variable and then substitute that expression into the other equation. Solving the first equation for $x$, we get $x = \frac{36 - 9y}{5}$. Substituting this into the second equation gives $3\left(\frac{36 - 9y}{5}\right) + 5y = 20$. Simplifying and solving for $y$ yields $y = 4$. Substituting $y = 4$ back into the expression for $x$ gives $x = 0$.

Solve the System of Equations by Substitution, If a Solution {5x+9y=363x+5y=20\left\{ \begin{array} { l } 5 x + 9 y = 36 \\3 x + 5 y = 20\end{array} \right.{5x+9y=363x+5y=20​

Solve the System of Equations by Substitution, If a Solution $\left\{ \begin{array} { l } 5 x + 9 y = 36 \\3 x + 5 y = 20\end{array} \right.$