Solve the inequality.
-$x ^ { 2 } - 6 x \geq - 8$
A) $x \geq 4$
B) $x \leq 2 \text { or } x \geq 4$
C) $x \leq 2$
D) $2 \leq x \leq 4$

Question

Quizplus · Accepted Answer

To solve the inequality $x^2 - 6x \geq -8$, first, we rewrite it in a standard form by adding 8 to both sides: $x^2 - 6x + 8 \geq 0$. Factoring the quadratic equation gives $(x-2)(x-4) \geq 0$. The roots are $x = 2$ and $x = 4$. The inequality is satisfied when $x \leq 2$ or $x \geq 4$, as these ranges make the product of $(x-2)(x-4)$ non-negative.

Solve the Inequality x2−6x≥−8x ^ { 2 } - 6 x \geq - 8x2−6x≥−8

Solve the Inequality $x ^ { 2 } - 6 x \geq - 8$