Solve the equation
-$6 x ^ { 2 / 5 } + 11 x ^ { 1 / 5 } + 4 = 0$
A) - $\frac { 1024 } { 243 } , - \frac { 1 } { 32 }$
B) $\frac { 1024 } { 243 } , \frac { 1 } { 32 }$
C) 3,2
D) - $\frac { 4 } { 3 } , - \frac { 1 } { 2 }$

Question

Quizplus · Accepted Answer

To solve the equation $6x^{2/5} + 11x^{1/5} + 4 = 0$, let $y = x^{1/5}$. Then the equation becomes $6y^2 + 11y + 4 = 0$, which is a quadratic equation. Factoring or using the quadratic formula, we find the roots for $y$. Substituting back $x^{1/5} = y$ and solving for $x$ gives the roots $-\frac{1024}{243}$ and $-\frac{1}{32}$.

Solve the Equation - 6x2/5+11x1/5+4=06 x ^ { 2 / 5 } + 11 x ^ { 1 / 5 } + 4 = 06x2/5+11x1/5+4=0

Solve the Equation
- $6 x ^ { 2 / 5 } + 11 x ^ { 1 / 5 } + 4 = 0$