Solve the inequality.
-$64 - x ^ { 2 } \geq 0$
A) $x \leq 8$
B) $- 8 \leq x \leq 8$
C) $x \leq - 8 \text { or } x \geq 8$
D) $x \leq - 32 \text { or } x \geq 32$

Question

Quizplus · Accepted Answer

To solve the inequality $64 - x^2 \geq 0$, we can rearrange it to $x^2 \leq 64$. Taking the square root of both sides gives $|x| \leq 8$, which means $x$ can be any number between -8 and 8, inclusive. This corresponds to option B: $-8 \leq x \leq 8$.

Solve the Inequality 64−x2≥064 - x ^ { 2 } \geq 064−x2≥0

Solve the Inequality $64 - x ^ { 2 } \geq 0$