Solve the inequality.
-$x ^ { 2 } + 10 x + 24 \geq 0$
A) $- 6 \leq x \leq - 4$
B) $x \leq - 6$
C) $x \geq - 4$
D) $x \leq - 6 \text { or } x \geq - 4$

Question

Quizplus · Accepted Answer

The inequality $x^2 + 10x + 24 \geq 0$ can be factored into $(x + 6)(x + 4) \geq 0$. The roots are $x = -6$ and $x = -4$. The inequality holds outside the interval $(-6, -4)$, thus the correct answer is $x \leq -6$ or $x \geq -4$.

Solve the Inequality x2+10x+24≥0x ^ { 2 } + 10 x + 24 \geq 0x2+10x+24≥0

Solve the Inequality $x ^ { 2 } + 10 x + 24 \geq 0$