Solve the inequality.
-$x ^ { 2 } + 6 x \leq - 8$
A) $x \leq 2 \text { or } x \geq 4$
B) $2

Name: Solve the inequality. -$x ^ { 2 } + 6 x \leq - 8$ A) $x \leq 2 \text { or } x \geq 4$ B) $2 < x < 4$ C) $2 \leq x \leq 4$ D) $- 4 \leq x \leq - 2$
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Question

Solve the inequality.
-$x ^ { 2 } + 6 x \leq - 8$
A) $x \leq 2 \text { or } x \geq 4$
B) $2 < x < 4$
C) $2 \leq x \leq 4$
D) $- 4 \leq x \leq - 2$

Quizplus · Accepted Answer

First, rearrange the inequality to standard form: $x^2 + 6x + 8 \leq 0$. Factoring gives $(x + 2)(x + 4) \leq 0$. The critical points are $x = -4$ and $x = -2$, and testing intervals shows that the inequality holds for $-4 \leq x \leq -2$.

Solve the Inequality x2+6x≤−8x ^ { 2 } + 6 x \leq - 8x2+6x≤−8

Solve the Inequality $x ^ { 2 } + 6 x \leq - 8$